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Question

Let ω being cube root of unity. Then the value of (1+ωω2)7 is

A
27
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B
27
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C
27ω3
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D
27ω2
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Solution

The correct option is B 27ω2
Now,
(1+ωω2)7

=(ω2ω2)7 [ Since 1+ω+ω2=0]

=(2ω2)7

=27ω2 [ Since ω14=(ω3)4.ω2=ω2] and [ω3=1]

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