Let ω=√3+i2 and P={ωn:n=1,2,3,⋯}. Further H1={z∈C:Rez>12} and H2={z∈C:Rez<−12}, where C is the set of all complex numbers. If z1∈P∩H1,z2∈P∩H2 and O represents the origin, then ∠z1Oz2=
A
π2
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B
π6
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C
2π3
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D
5π6
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Solution
The correct option is D5π6 ω=√3+i2=eiπ/6 P={ωn:n=1,2,3,⋯} ⇒P=ei(nπ/6),|P|=1 ⇒P lies on a unit circle centred at origin lying at a difference of angle of π6.
H1={z∈C:Rez>12} and H2={z∈C:Rez<−12}
Now, for z1,cos(nπ6)>12
So, possible positions of z1 are A,L and K.
Similarly, for z2,cos(nπ6)<−12
So, possible positions of z2 are E,F and G.