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Question

Let a=2^i+3^j^k,b=^i+2^j4^k,c=^i+^j+^k, d=^i^j^k, then (a×b).(c×d) is equal to

A
24
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B
16
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C
8
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D
4
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Solution

The correct option is D 4
Scalar product of four vectors (a×b).(c×d)
∣ ∣a.ca.db.cb.d∣ ∣
(2^i+3^j^k).(^i+^j+^k)(2^i+3^j^k).(^i^j^k)(^i+2^j4^k).(^i+^j+^k)(^i+2^j4^k).(^i^j^k)
(2+31)(23+1)(1+24)(12+4)
4031=40=4

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