CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let a=2^i+^j2^k and b=^i+^k. If c is a vector such that a.c=c,ca=22 and the angle between (a×b) and c is 300, then (a×b)×c=

A
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 32
ca=22
squaring both sides, we get
c22c+9=8
c22c+1=0
(c1)2=0
c=1
a×b=∣ ∣ ∣^i^j^k212110∣ ∣ ∣
=2^i2^j+^k on simplification
a×b=4+4+1=9=3
Now , (a×b)×c=a×bcsin300
=3×1×12=32

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle between Two Lines
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon