Let →a=3^i+2^j+2^k and →b=^i+2^j−2^k be two vectors. If a vector perpendicular to both the vectors →a+→b and →a−→b has the magnitude 12 then one such vector is :
A
4(2^i+2^j+^k)
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B
4(2^i+2^j−^k)
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C
4(2^i−2^j−^k)
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D
4(−2^i−2^j+^k)
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Solution
The correct option is C4(2^i−2^j−^k) →a=3^i+2^j+2^k →b=^i+2^j−2^k →a+→b=4^i+4^j →a−→b=2^i+4^k As a vector →rperpendicular to both the vectors →a+→b and →a−→b has the magnitude 12 →r=12⋅^n ^n=(→a+→b)×(→a−→b)∣∣∣(→a+→b)×(→a−→b)∣∣∣