wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let A=Acosθ^i+Asinθ^j be any vector.Then another vector B which is normal to A can be?


A

B cos + B sin

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

B sin + B cos

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

B sin - B cos

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

B cos - B sin

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

B sin - B cos


Dot product of two perpendicular vectors is zero

We need a vector B such that,A.B = 0 If we consider option (c)

A.B = AB sinθcosθ

= 0

Answer is (C)


flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon