Let →A=Acosθ^i+Asinθ^j be any vector.Then another vector →B which is normal to →A can be?
B sin - B cos
Dot product of two perpendicular vectors is zero
∴ We need a vector →B such that,→A.→B = 0 If we consider option (c)
→A.→B = AB sinθcosθ
= 0
∴ Answer is (C)