Let →a and →b be two vectors of equal magnitude 5 uints. Let →p,→q be vectors such that →p=→a−→b and →q=→a+→b. If |→p×→q|=2{γ−(→a.→b)2}1/2, then the value of γ is
A
5
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B
25
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C
125
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D
625
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Solution
The correct option is D625 |→p×→q|=2{γ−(→a.→b)2}1/2⋯(1) →p×→q=(→a−→b)×(→a+→b) ⇒→p×→q=2(→a×→b) ⇒→p×→q=2|→a||→b|sinθ ⇒→p×→q=50√1−cos2θ⇒→p×→q=2√625−625cos2θ
We know that, →a⋅→b=|→a||→b|cosθ=25cosθ
Using the equation (1), 2√625−625cos2θ=2{γ−(→a.→b)2}1/2⇒2√625−625cos2θ=2{γ−625cos2θ}1/2 ⇒γ=625