Let a- and b- be two vectors with -a-13-b-19 and -a-b-22- The value of -a-b- is

The correct option is D 24As we know that nbsp; nbsp;|a+b|^2+ nbsp;|a b|^2=2( nbsp;|a|^2+|b|^2) nbsp;⇒ |a+b|^2=2( nbsp;13^2+19^2) 22^2 ...

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Collinear Vectors

Let a⃗ and b⃗...

Question

Let $\to a$ and $\to b$ be two vectors with $| \to a | = 13,$ $| \to b | = 19$ and $| \to a - \to b | = 22.$ The value of $| \to a + \to b |$ is

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Solution

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Similar questions

\to a

\to b

\frac{{∣ ∣ \to a + \to b ∣ ∣}^{2} - {∣ ∣ \to a - \to b ∣ ∣}^{2}}{{∣ ∣ \to a + \to b ∣ ∣}^{2} + {∣ ∣ \to a - \to b ∣ ∣}^{2}}

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

\to a

\to b

| \to a + \to b | = 13

| \to a | = 5

| \to b | .

| \to a | \to b + | \to b | \to a

| \to a | \to b - | \to b | \to a

\to a

\to b

| \to a | \to b + | \to b | \to a

| \to a | \to b - | \to b | \to a

\to a

\to b

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