Let →a be a vector which is perpendicular to thevector 3^i+12^j+2^k. If →a×(2^i+^k)=2^i−13^j−4^k, then the projection of the vector a on the vector 2^i+2^j+^k is :
A
1
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B
73
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C
13
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D
53
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Solution
The correct option is D53 Let →a=a1^i+a2^j+a3^k
and →a.(3^i−12^j+2^k)=0⇒3a1+a22+2a3=0...(i)
and →a×(2^i+^k)=2^i−13^j−4^k ⇒a2^i+(2a3−a1)^j−2a2^k=2^i−13^j−4^k ∴a2=2 ...(ii)
and a1−2a3=13 ...(iii)
From eq. (i) and (ii) : a1=3 and a3=−5 ^∴→a=3^i+2^j−5^k