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Question

Let a be a vector which is perpendicular to thevector 3^i+12^j+2^k. If a×(2^i+^k)=2^i13^j4^k, then the projection of the vector a on the vector 2^i+2^j+^k is :

A
1
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B
73
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C
13
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D
53
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Solution

The correct option is D 53
Let a=a1^i+a2^j+a3^k
and a.(3^i12^j+2^k)=03a1+a22+2a3=0...(i)

and a×(2^i+^k)=2^i13^j4^k
a2^i+(2a3a1)^j2a2^k=2^i13^j4^k
a2=2 ...(ii)
and a12a3=13 ...(iii)
From eq. (i) and (ii) : a1=3 and a3=5
^a=3^i+2^j5^k

Projection of a on 2^i+2^j+^k=6+453=53

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