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Question

Let a=^i+^j+2^k,b=b1^i+b2^j+2^k and c=5^i+^j+2^k be three vectors such that the projection vector of b on a is a. If a+b is perpendicular to c, then |b| is equal to :

A
6
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B
4
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C
22
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D
32
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Solution

The correct option is A 6
Given, Projection of b on a is a.
b.a|a|=|a|

b1+b2+21+1+2=1+1+2

b1+b2=2 ...(1)

Since, a+b is perpendicular to c
So, (a+b)c=0
ac+bc=0
(5+1+2)+(5b1+b2+2)=0
5b1+b2=10 ...(2)

From Equations (1) and (2),
b1=3, b2=5
b=3^i+5^j+2^k
Hence, |b|=9+25+2
|b|=6

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