Let a - -k- - c - - -k- Then the vector b satisfying a - b - c -0 and a - b -3 is

The correct option is D î +ĵ 2k̂ Given a⃗ = ĵ k̂ c⃗= î ĵ k̂ let b⃗ = b_1î+b_2ĵ+b_3k̂ a⃗.b⃗ = 3 ⇒ (ĵ k̂).(b_1î+b_2ĵ+b_3k̂) = 3 ...

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Applications of Dot Product

Let a =ĵ -k...

Question

Let $\to a =^j -^k; \to c =^i -^j -^k$ . Then the vector $\to b$ satisfying $\to a \times \to b + \to c = 0$ and $\to a . \to b = 3$ is

2^i -^j + 2^k

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^i -^j - 2^k

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^i - +^j - 2^k

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-^i +^j - 2^k

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Solution

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Similar questions

\to a =^j -^k; \to c =^i -^j -^k

\to b

\to a \times \to b + \to c = \to 0

\to a . \to b = 3

\sqrt{2}

\to a =^i +^j + 2^k

\to b =^i + 2^j +^k

\to c =^i +^j +^k

-^i -^k

^j -^k

^i -^j

^i +^k

\to a =^i +^j - 2^k,

{∣ ∣ (\to a \times^i) \times^j ∣ ∣}^{2} + {∣ ∣ (\to a \times^j) \times^k ∣ ∣}^{2} + {∣ ∣ (\to a \times^k) \times^i ∣ ∣}^{2} =

a = -^i +^j + 2^k

b = 2^i -^j -^k

c = - 2^i +^j + 3^k

\to a . (\to b \times \to c)

\to a = 2^i +^j + 3^k, \to b = -^i + 2^j +^k a n d \to c = 3^i +^j + 2^k

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