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Negative of a Vector

Let a =ĵ -k...

Question

Let $\to a =^j -^k; \to c =^i -^j -^k$ . Then the vector $\to b$ satisfying $\to a \times \to b + \to c = 0$ and $\to a . \to b$ is

A

^i +^j - 2^k

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B

-^i +^j - 2^k

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C

2^i -^j + 2^k

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D

^i -^j - 2^k

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Solution

The correct option is B $-^i +^j - 2^k$
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Similar questions

Q. A vector of magnitude

\sqrt{2}

coplanar with the vectors

\to a =^i +^j + 2^k

\to b =^i + 2^j +^k

and perpendicular to the vector

\to c =^i +^j +^k

-^i -^k

^j -^k

^i -^j

^i +^k

\to a =^i +^j - 2^k,

{∣ ∣ (\to a \times^i) \times^j ∣ ∣}^{2} + {∣ ∣ (\to a \times^j) \times^k ∣ ∣}^{2} + {∣ ∣ (\to a \times^k) \times^i ∣ ∣}^{2} =

¯ ¯ ¯ a =^i +^j - 2^k, ¯ ¯ b = 2^i -^j +^k

¯ ¯ c = 3^i +^k

¯ ¯ c = m ¯ ¯ ¯ a + n ¯ ¯ b

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b = 2^i -^j -^k

c = - 2^i +^j + 3^k

, then the angle between 2a-c and a+b is:

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^i +^j + 2^k

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and perpendicular to

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