Let →a,→b and →c be three vectors such that |→a|=3,|→b|=4,|→c|=5 and mutually perpendicular to each other, then |→a+→b+→c|=
5
10
|→a+→b+→c|2=|→a|2+|→b|2+|→c|2=50∴|→a+→b+→c|=5√2