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Question

Let a,b and c be three vectors such that |a|=3,|b|=5,b.c=10 and the angle between b and c is π3.
If a is perpendicular to vector b×c, then |a×(b×c)| is equal to

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Solution

|a×(b×c)|=|a||b×c|sinθ where θ is angle between a and b×c
θ=π2 (given)
|a×(b×c)|=3|b×c|sinπ2
|a×(b×c)|=3|b||c|sinπ3
|a×(b×c)|=3×5×|c|×32
|a×(b×c)|=152|c|
Now, |b||c|cosθ=10
5|c|12=10
|c|=4
|a×(b×c)|=30

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