Let →a,→b,→c be three unit vectors such that →b×(→c×→a)=→c2. If →a and →c are non-parallel, then the angles which →b makes with →c and→a are respectively
A
30° & 60°
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B
60° & 45°
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C
30° & 90°
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D
90° & 60°
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Solution
The correct option is D90° & 60° →b×(→c×→a)=→c2⇒(→b⋅→a)→c−(→b⋅→c)→a=→c2⇒((→b⋅→a)−12)→c=(→b⋅→c)→a
Since →a and →c are non-parallel unit vectors therefore ⇒→b⋅→c=0=cos90° ⇒→a⋅→b=12=cos60°