Let a-b-c be unit vectors and - be the angles between b-c-c-a-a-b respectively-If -a-b-c-1- the cos-cos-cos-

The correct option is B 1 |a+b+c|=1 ⇒|a+b+c|^2=1 ⇒|a|^2+|b|^2+|c|^2+2.a.b+2.b.c+2.c.a=1 nbsp;since a,b,c are unit vectors ⇒ 1 ...

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Angle between Two Lines

Let a,b,c b...

Question

Let $\to a, \to b, \to c$ be unit vectors and $α, β, γ$ be the angles between $\to b, \to c; \to c, \to a; \to a, \to b$ respectively.If $∣ ∣ ∣ \to a + \to b + \to c ∣ ∣ ∣ = 1$ , the $cos α + cos β + cos γ =$

0

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\frac{3}{2}

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a = cos α + i sin α, b = cos β + i sin β, c = cos γ + i sin γ

\frac{a}{b} + \frac{b}{c} + \frac{c}{a} = - 1

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\frac{b}{c} + \frac{c}{a} + \frac{a}{b} = 1

c o s (β - γ) + c o s (γ - α) + c o s (α - β) i s e q u a l t o

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If a=cos $α$ +isin $α$ , b=cos $β$ +isin $β$ ,

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