Let - - - be three unit vectors such that -0 and the angle between - and - is 30- Then - is A- 2- y B- -2- y C- - 2-D- -

The correct option is C ±2(β×γ) nbsp; nbsp;α.β= α. γ=0 ⇒α is perpendicular to both β and γ. ⇒α= n (β×γ) ⇒1 = |n| × 1 × 1 ×sin 30^∘ ⇒ n = ± 2 nbsp; nbsp ...

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Byju's Answer

Standard XII

Mathematics

Area between Two Curves

Let α⃗, β⃗, γ...

Question

Let $\to α, \to β, \to γ$ be three unit vectors such that $\to α . \to β = \to α . \to γ = 0$ and the angle between $\to β$ and $\to γ$ is $30^{\circ} .$ Then $\to α$ is

2 (\to β \times \to γ)

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- 2 (\to β \times \to γ)

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\pm 2 (\to β \times \to γ)

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(\to β \times \to γ)

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Solution

The correct option is C $\pm 2 (\to β \times \to γ)$
$\to α . \to β = \to α . \to γ = 0$
$\Rightarrow \to α$ is perpendicular to both $\to β$ and $\to γ$ .
$\Rightarrow \to α = n (\to β \times \to γ)$
$\Rightarrow 1 = | n | \times 1 \times 1 \times sin 30^{\circ}$
$\Rightarrow n = \pm 2$

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Let →α,→β,→γ be three unit vectors such that →α.→β=→α.→γ=0 and the angle between →β and →γ is 30∘. Then →α is

The correct option is C ±2(→β×→γ) →α.→β=→α.→γ=0 ⇒→α is perpendicular to both →β and →γ. ⇒→α=n(→β×→γ) ⇒1=|n|×1×1×sin30∘ ⇒n=±2

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