Let →c1=(1,0,0),→c2=(1,1,0),→c3=(1,1,1), and (→c1,→c2,→c3) forms a system, then reciprocal of →c1=
A
^i+^j
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
^i−^j
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
^j−^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
^k−^i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B^i−^j we know,
Reciprocal of →c1=→c2×→c3[→c1→c2→c3]⋯(i) →c2×→c3=∣∣
∣
∣∣^i^j^k110111∣∣
∣
∣∣=^i−^j
and [→c1→c2→c3]=∣∣
∣∣100110111∣∣
∣∣=1
putting these values in (i),
we get, reciprocal of →c1=^i−^j