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Question

Let c=x^i+y^j+z^k is the external angle bisector between two vectors a=2^i^j+3^k and b=^i+2^j3^k,|c|=346. Then x+y+z=

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Solution

Given vectors, a=2^i^j+3^k and b=^i+2^j3^k,
external angle bisector is λ(^a^b)
c=λ(2^i^j+3^k14^i+2^j3^k14)=λ14(^i3^j+6^k)|c|=46λ14=346λ=314c=3^i9^j+18^kx+y+z=39+18=12

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