Let p-q-r be three mutually perpendicular vectors of same magnitude-If a vector x satisfies the equation p-x-q-p-q-x-r-q-r-x-p-r-0 then x-

The correct option is B 12(p+q+r) p=pî,q=pĵ,r=pk̂ p×((x q)×p)+q×((x r)×q)+r×((x p)×r)=0 ⇒∑p×((x q)×p)+q× ⇒∑pî×((x pĵ)× pî)+pĵ =∑p ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Orthogonal System of Vectors

Let p,q,r b...

Question

Let $\to p, \to q, \to r$ be three mutually perpendicular vectors of same magnitude.If a vector $\to x$ satisfies the equation
$\to p \times ((\to x - \to q) \times \to p) + \to q \times ((\to x - \to r) \times \to q) + \to r \times ((\to x - \to p) \times \to r) = 0$ then $\to x =$

\frac{1}{2} (\to p + \to q - 2 \to r)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2} (\to p + \to q + \to r)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{3} (\to p + \to q + \to r)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3} (2 \to p + \to q - \to r)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to p, \to q, \to r

\to x

\to p [(\to x - \to q) \times \to p] + \to q \times [(\to x - \to r) \times \to q] + \to r \times [(\to x - \to p) \times \to r] = \to 0

\to x

\to p, \to q, \to r

\to x

\to p \times (\to x - \to q \times \to p) + \to q \times (\to x - \to r \times \to q) + \to r \times (\to x - \to p \times \to r) = 0

\to x

p, q, r

x

p \times ((x - q) \times p) + q \times ((x - r) \times q) + r \times ((x - p) \times r) = 0,

x

\to p, \to q, \to r

\to x

\to p \times ((\to x - \to q) \times \to p) + \to q \times ((\to x - \to r) \times \to q) + \to r \times ((\to x - \to p) \times \to r) = 0

\to x

\to p, \to q, \to r

\to x

\to p \times {(\to x - \to q) \times \to p} + \to q \times {(\to x - \to r) \times \to q} + \to r \times {(\to x - \to p) \times \to r}

Join BYJU'S Learning Program