Let u and v be unit vectors- If w is a vector such that w - w - u - v- then maximum value of 2- u - v - w - is

[uvw]=(u×v).(v (w×u)) =(u×v).(u×w) =u.u amp;u.wv.u amp; v.w w+ (w×u)=v Taking dot product with u u.w =u.v Taking dot product ...

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Acceleration in 2D

Let u and v b...

Question

Let $\to u$ and $\to v$ be unit vectors. If $\to w$ is a vector such that $\to w + (\to w \times \to u) = \to v$ , then maximum value of $2 | (\to u \times \to v) . \to w |$ is

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\to u

\to v

\to u \times \to v + \to u = \to w

\to w \times \to u = \to v,

[\to u, \to v, \to w]

\to u, \to v

\to w

\to u + \to v + \to w = \to 0 .

| \to u | = 3, | \to v | = 4

| \to w | = 5,

\to u . \to v + \to v . \to w + \to w . \to u

\to u, \to v

\to w

\to u + \to v + \to w = \to 0 .

| \to u | = 3, | \to v | = 4

| \to w | = 5,

\to u . \to v + \to v . \to w + \to w . \to u

u, v

w

u + v + w = 0

| u | = 3, | v | = 4

| w | = 5

u . v + v . w + w . u

\vec{u,} \vec{v} and \vec{w}

\vec{u} + \vec{v} + \vec{w} = \vec{0} .

|\vec{u}| = 3, |\vec{v}| = 4 and |\vec{w}| = 5,

\vec{u} \cdot \vec{v} + \vec{v} \cdot \vec{w} + \vec{w} \cdot \vec{u} .

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