Let →x,→y and →z be three vectors each of magnitude √2 and the angle between each pair of them is π3. If →a is a non-zero vector perpendicular to →x and →y×→z and →b is a non-zero vector perpendicular to →y and →z×→x, then
A
→b=(→b⋅→z)(→z−→x)
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B
→a=(→a⋅→y)(→y−→z)
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C
→a⋅→b=−(→a⋅→y)(→b⋅→z)
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D
→a=−(→a⋅→y)(→z−→y)
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Solution
The correct options are A→b=(→b⋅→z)(→z−→x) B→a=(→a⋅→y)(→y−→z) C→a⋅→b=−(→a⋅→y)(→b⋅→z) →a is in direction of →x×(→y×→z) i.e. (→x⋅→z)→y−(→x⋅→y)→z ⇒→a=λ1[2×12(→y−→z)] →a=λ1(→y−→z) ...... (1)
Now →a⋅→y=λ1(→y⋅→y−→y⋅→z) =λ1(2−1)⇒λ1=→a⋅→y ......(2)