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Byju's Answer
Standard XII
Mathematics
Inclination of a Line
Let P=-1, 0...
Question
Let
P
=
(
−
1
,
0
)
,
Q
=
(
0
,
0
)
and
R
=
(
√
3
,
3
)
be three points. The equation of the bisector of angle PQR is?
A
√
3
x
+
y
=
0
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B
x
+
(
√
3
2
)
y
=
0
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C
(
√
3
2
)
x
+
y
=
0
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D
x
−
√
3
y
=
0
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Solution
The correct option is
A
√
3
x
+
y
=
0
Given three points
p
(
−
1
,
0
)
Q
(
0
,
0
)
R
(
3
,
3
√
3
)
Slope of the line
Q
M
is
t
a
n
2
π
2
=
−
√
3
∴
Equation is line
Q
M
which is
y
=
−
√
3
x
⟹
√
3
x
+
y
=
0
Suggest Corrections
0
Similar questions
Q.
Let
P
=
(
−
1
,
0
)
,
Q
=
(
0
,
0
)
and
R
=
(
3
,
3
√
3
)
be three points. The equation of the bisector of the angle
P
Q
R
is
Q.
Let
P
=
(
−
1
,
0
)
,
Q
=
(
0
,
0
)
,
a
n
d
R
=
(
3
,
3
√
3
)
be three points. Then the equation of the bisector of
∠
P
Q
R
is
Q.
Let
P
=
(
−
1
,
0
)
,
Q
=
(
0
,
0
)
,
a
n
d
R
=
(
3
,
3
√
3
)
be three points. Then the equation of the bisector of
∠
P
Q
R
is
Q.
Let
P
=
(
−
1
,
0
)
,
Q
=
(
0
,
0
)
and
R
=
(
3
,
3
√
3
)
be three points, Then the equation of the bisector of the angle PQR is -
Q.
Let
P
=
(
−
1
,
0
)
,
Q
=
(
0
,
0
)
and
R
=
(
3
,
3
√
3
)
be three points, then the equation of the bisector of the
∠
PQR is -
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