Question

Let $P=(-1,0),Q=(0,0)$ and $R=(3,3\sqrt{3})$ be three points. Then the equation of the bisector of the angle $PQR$ is

• A. $\frac{\sqrt{3}}{2}x+y=0$
• B. $x+\sqrt{3}y=0$
• C. $\sqrt{3}x+y=0$
• D. $x+\frac{\sqrt{3}}{2}y=0$

Answer 1

The correct option is C $\sqrt{3}x+y=0$

Slope of line $QM$ is $\tan \frac{2\pi }{3}=-\sqrt{3}$

Hence equation of line $QM$ is

$y=-\sqrt{3}x$

$y+\sqrt{3}x=0$

$\sqrt{3}x+y=0$