Let -p - 4 is a root of x2-2 x-2-0 - and -q - Room temperature is 13- C - be two statements- Then - p - q is the statementA- 4 is not a root of x2-2 x-2-0 or room temperature is 13- CB- 4 is not a root of x2-2 x-2-0 or room temperature is not 13- CC- 4 is a root of x2-2 x-2-0 or room temperature is 13- CD- 4 is a root of x 2-2 x -2-0 and room temperature is 13- C

The correct option is B 4 is not a root of x^2+2x+2=0 or room temperature is not 13^∘ Cp: 4 is a root of x^2+2x+2=0 q: Room temperature is 13^∘ C ∼(p q)= ∼ p ...

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Byju's Answer

Standard XII

Mathematics

Negation

Let "p : 4 is...

Question

Let " $p : 4$ is a root of $x^{2} + 2 x + 2 = 0$ " and " $q :$ Room temperature is $13^{\circ} C$ " be two statements. Then $\sim (p \land q)$ is the statement

4

is not a root of

x^{2} + 2 x + 2 = 0

or room temperature is

13^{\circ} C

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4

is not a root of

x^{2} + 2 x + 2 = 0

or room temperature is not

13^{\circ} C

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4

is a root of

x^{2} + 2 x + 2 = 0

or room temperature is

13^{\circ} C

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4

is a root of

x^{2} + 2 x + 2 = 0

and room temperature is

13^{\circ} C

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Solution

The correct option is B $4$ is not a root of $x^{2} + 2 x + 2 = 0$ or room temperature is not $13^{\circ} C$
$p :$ $4$ is a root of $x^{2} + 2 x + 2 = 0$
$q :$ Room temperature is $13^{\circ} C$

$\sim (p \land q) = \sim p \lor \sim q$
$\sim (p \land q) :$ $4$ is not a root of $x^{2} + 2 x + 2 = 0$ or room temperature is not $13^{\circ} C$

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Let "p:4 is a root of x2+2x+2=0" and "q: Room temperature is 13∘C" be two statements. Then ∼(p∧q) is the statement

The correct option is B 4 is not a root of x2+2x+2=0 or room temperature is not 13∘Cp: 4 is a root of x2+2x+2=0 q: Room temperature is 13∘C ∼(p∧q)= ∼p ∨∼q ∼(p∧q): 4 is not a root of x2+2x+2=0 or room temperature is not 13∘C

Let " $p : 4$ is a root of $x^{2} + 2 x + 2 = 0$ " and " $q :$ Room temperature is $13^{\circ} C$ " be two statements. Then $\sim (p \land q)$ is the statement