Let P=[aij] be a 3×3 matrix and let Q=[bij], where bij=2i+jaij. for 1≤i,j≤3. If the determinant of P is 2, then the determinant of the matrix Q is
A
210
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B
211
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C
212
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D
213
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Solution
The correct option is B213 P(X)=∣∣
∣∣a11a12a13a21a22a23a31a32a33∣∣
∣∣
Q=[bij]=2i+jaij Q=∣∣
∣
∣∣22a1123a1224a1323a2124a2225a2324a3125a3226a33∣∣
∣
∣∣ Taking 22,23,and24 common from 1st, 2nd and 3rd row respectively, we get Q=29∣∣
∣
∣∣a112a1222a13a212a2222a23a312a3222a33∣∣
∣
∣∣
Now taking 2,22 common from 2nd and 3rd column respectively, we get