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Question

Let Pi and Pi be the feet of the perpendiculars drawn from foci S,S on a tangent Ti to an ellipse whose length of semi-major axis is 20. If 10i1(SPi)(SPi)=2560, then the value of eccentricity is:

A
15
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B
25
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C
35
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D
45
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Solution

The correct option is D 35
Given: 10i=1(SPi)(SPi)=2560

we know that SP.SP to any tangent T of the ellipse=b2

10b2=2560

b2=256

Given length of semi major axis is 20

so, e=1b2a2=400256400=1220=35


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