Let Pi and P′i be the feet of the perpendiculars drawn from foci S,S′ on a tangent Ti to an ellipse whose length of semi-major axis is 20. If 10∑i−1(SPi)(S′P′i)=2560, then the value of eccentricity is:
A
15
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B
25
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C
35
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D
45
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Solution
The correct option is D35 Given: ∑10i=1(SPi)(S′P′i)=2560
we know that SP.S′P′ to any tangent T of the ellipse=b2