Question

Let $P=\left(-1,0\right)Q=\left(0,0\right)andR=\left(3,3\sqrt{3}\right)$ be three points. The equation of the bisector of the $\angle PQR$ is

Answer 1

slope of line QR is $\frac{3\sqrt{3}-0}{3-0}$

$=\sqrt{3}$

so angle of elevation is $ta{n}^{-}1\left(slope\right)$

$=ta{n}^{-}1\left(\sqrt{3}\right)$

$=60$

therefore slope of angular bisector of PQR is $60+60$

$=120$

slope is $tan120$

$=-\sqrt{3}$

angule bisector is passing through $(0,0)$

so equation of angle bisector is $y=-\sqrt{3}x$