Let P=⎡⎢⎣3−1−220α3−50⎤⎥⎦, where α∈R. Suppose Q=[qn] is a matrix such that PQ=kl, where k∈R,k≠0 and l is the identity matrix of order 3. if q23=−k8 and det(Q)=k22, then
A
α=0,k=8
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B
4a−k+8=0
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C
det(Padj(Q))=29
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D
det(Qadj(P))=213
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Solution
The correct options are B4a−k+8=0 Cdet(Padj(Q))=29