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Question

Let P(n)=5n2n,P(n) is divisible by 3λ where λ and n both are odd positive integers then the least value of n and λ will be

A
13
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B
11
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C
1
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D
5
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Solution

The correct option is C 1
P(n)=5n2n
Let λ=1, we get P(1)=5121=3
Similarly for,n=5,P(5)=5525=312532=3093=3×1031
In this case λ=1031
Similarly we can check the result for other cases and find that the least value of λ and n is 1.
Ans: C

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