Let P(n)=5n−2n,P(n) is divisible by 3λ where λ and n both are odd positive integers then the least value of n and λ will be
A
13
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B
11
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C
1
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D
5
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Solution
The correct option is C1 P(n)=5n−2n Let λ=1, we get P(1)=51−21=3 Similarly for,n=5,P(5)=55−25=3125−32=3093=3×1031 In this case λ=1031 Similarly we can check the result for other cases and find that the least value of λ and n is 1. Ans: C