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Question

Let P={x:xN and 7x+2>1} and Q={x:xN and |x1|<2}. Then n(PΔQ) is

A
7
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B
8
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C
2
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D
4
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Solution

The correct option is C 2
7x+2>1
7x+21>0
5xx+2>0
x5x+2<0
x(2,5)
P={1,2,3,4}

|x1|<2
2<x1<2
1<x<3
Q={1,2}

n(PΔQ)=n(P)+n(Q)2n(PQ)
=4+22×2
=2

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