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Question

Let $$P=\left\{ (x,y)|{ x }^{ 2 }+{ y }^{ 2 }=1,x,y\in R \right\} $$. Then $$P$$ is


A
reflexive
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B
symmetric
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C
tansitive
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D
anti-symmetric
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Solution

The correct option is A symmetric
Obviously, the relation is not reflexive and transitive but it is symmetric, because
$${x}^{2}+{y}^{2}=1 \Rightarrow {y}^{2}+{x}^{2}=1$$

Mathematics

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