Question

# Let $$P=\left\{ (x,y)|{ x }^{ 2 }+{ y }^{ 2 }=1,x,y\in R \right\}$$. Then $$P$$ is

A
reflexive
B
symmetric
C
tansitive
D
anti-symmetric

Solution

## The correct option is A symmetricObviously, the relation is not reflexive and transitive but it is symmetric, because$${x}^{2}+{y}^{2}=1 \Rightarrow {y}^{2}+{x}^{2}=1$$Mathematics

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