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Question

Let p=limx0+(1+tan2x)12x then log p is equal to:

A
12
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B
14
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C
2
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D
1
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Solution

The correct option is A 12
lnP=limx0+12xln(1+tan2x)limx0+1xln(secx)
Applying L hospital's rule:
=limx0+secxtanxsecx.2x=limx0+tanx2x=12

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