Let P(m,n) be the foot of the perpendicular from the point Q(2,3) on the line x+y−11=0. If r and s are non-negative integers, then the maximum value of mCr+nCs is
A
20
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B
30
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C
40
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D
25
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Solution
The correct option is B30 Given, P(m,n) is the foot of the perpendicular from Q(2,3) on the line x+y−11=0. ∴m−21=n−31=−(2+3−11)12+12=3 ⇒m=5,n=6
mCr+nCs =5Cr+6Cs 5Cr is maximum when r=5+12=3
and 6Cs is maximum when s=62=3 ∴ Maximum value of mCr+nCs is 5C3+6C3 =10+20=30