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Question

Let Pn=apn11, n =2,3,.... and let P1=ax1 where aR+ then evaluate limx0Pnx

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Solution

P1=(ax1)P2=(aP11)=(a(ax1)1)P3=(aP21)=(a(a(ax1)1)1)
We know that limx0ax1x=1
In P2=(a(ax1)1)limx0P2x=limx0a(ax1)xx1x=limx0ax1x=1
In P3=(a(a(ax1)1)1)limx0P3x=limx0(a(a(ax1)1)1)x=limx0(a(a(ax1)xx1)1)xlimx0a(ax1)xx1x=limx0ax1x=1
Hence,
limx0Pnx=(a(a(a(a(a(ax1)1)1)1)1)1)x=1

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