Question

Let P(n) denote the statement that $n^2+n$ is odd. It is seen that $P\left(n\right)\Rightarrow P(n+1),P\left(n\right)$ is true for all.

• A. $n>1$
• B. n
• C. $n>2$
• D. None of these

Answer 1

Answer: (D)

None of these

$P\left(n\right)=n^2+n$. It is always odd (by statement) but square of any odd and

also, sum of two odd number is always even. So, for no any 'n' for which its statement is true.