Let Pn denote the statement that n2-n is odd- It is seen that Pn- Pn-1- Pn is true for all-

The correct option is B None of these P(n)=n^2+n . It is always odd (by statement) but #160;square #160;of any odd and #160;also, #160;sum #160;o ...

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Fallacy

Let Pn denote...

Question

Let P(n) denote the statement that $n^{2} + n$ is odd. It is seen that $P (n) \Rightarrow P (n + 1), P (n)$ is true for all.

n > 1

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n > 2

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None of these

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Solution

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Similar questions

Let P(n) denote the statement that $n^{2}$ + n is odd. It

is seem that P(n) ⇒ P(n + 1), $P_{n}$ is true for all

Let P(n) denote the statement that $n^{2}$ + n is odd. Then,

P (n) : n^{2} + n

P (n) \Rightarrow

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P (n) = P (n + 1) \forall n \in N

P (n)

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Let P(n) be the statement : $2^{n} \leq 3 n$ . If P(r) is true, show that P(r + 1) is true. Do you conclude that P(n) is true for all $n ϵ N$ .

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