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Question

Let p,q0 and let the roots of the equation x2+px+q=0 be α,β then find the equation whose roots are 1α,1β.

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Solution

Given the roots of the equation x2+px+q=0 be α,β.......(1).
To find the equation whose roots are 1α,1β let us put 1x in stead of x in (1).
Then we get,
1x2+p1x+q=0
or, qx2+px+1=0
This is the required equation.

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