Let P- Q-R be points with position vectors r-1 -3i-2j- -k- r-2 -i- - 3j- - 4k- and r-3- 2i- - j- -2k- relative to an origin O- The distance of P from the plane OQR is magnitude

The correct option is B 3 P,Q,R be points with position vectors r_1 =3i⃗ 2j⃗ k⃗, r_2 =i⃗ + 3j⃗ + 4k⃗ and r_3= 2i⃗ +#160;j 2k⃗ Equation ...

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Perpendicular Distance of a Point from a Plane

Let P, Q,R ...

Question

Let $P, Q, R$ be points with position vectors ${\to r}_{1} = 3 \to i - 2 \to j - \to k, {\to r}_{2} = \to i + 3 \to j + 4 \to k$ and ${\to r}_{3} = 2 \to i + \to j - 2 \to k$ relative to an origin $O$ . The distance of $P$ from the plane $O Q R$ is (magnitude)

2

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3

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1

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\frac{11}{\sqrt{3}}

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Solution

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Similar questions

L_{1}

{\to r}_{1} = 2 \to i + \to j - \to k + λ (\to i + 2 \to k)

L_{2}

{\to r}_{2} = 3 \to i + \to j + μ (\to i + \to j - \to k)

π

L_{1}

L_{2}

π

\to r = 3 \to i + 2 \to j - 5 \to k

\to a = 2 \to i - \to j + \to k

\to b = \to i + 3 \to j - 2 \to k

\to c = - 2 \to i + \to j - 3 \to k

\to r = λ \to a + μ \to b + ν \to c

3 \to i + 4 \to j + 2 \to k, 2 \to i - 2 \to j - \to k

7 \to i + \to j + \to k

A, B

C

2 \to i - \to j + \to k, \to i - 3 \to j - 5 \to k

3 \to i - 4 \to j - 4 \to k

{cos}^{2} A

2 \to i + 3 \to j + 4 \to k, 3 \to i + 2 \to j - 3 \to k

5 \to i + 5 \to j + \to k

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