Let p-q-r be three simple statements- Then- - p- q- p- r is equal to

The correct option is B (∼ p)∧ (∼ q∨∼ r) Given, #160; ∼ (p∨ q)∧∼ (p∨ r) =(∼ p∧∼ q)∨ (∼ p∧∼ r) =(∼ #160; p)∧ (∼ q∨∼ r) (Using distributiv ...

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Contra-Positive

Let p,q,r b...

Question

Let $p, q, r$ be three simple statements. Then, $\sim (p \lor q) \lor \sim (p \lor r)$ is equal to

(\sim p) \land (\sim q \lor \sim r)

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(\sim p) \land (q \land r)

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p \land (q \lor r)

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p \lor (q \land r)

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(p \lor q) \land r

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Solution

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Similar questions

p, q, r

\sim (p \lor (q \land r))

The dual of statement $p \lor (q \land r) \equiv (p \lor q) \land (p \lor r)$ is

Factorise: $(p^{2} + q^{2} - r^{2})^{2} - 4 p^{2} q^{2}$

P : [(⇁ p \lor q) \land (r \to s) \land (p \lor r)] \to (⇁ s \to q)

Q : [(⇁ p \land q) \land [q \to (p \to r)]] \to⇁ r

R : [[(q \land r) \to p] \land (⇁ q \lor p)] \to r

S : [p \land (p \to r) \land (q \lor ⇁ r)] \to q

p, q, r

p \Rightarrow (q \lor r)

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