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Question

Let P(x) be a polynomial, which when divided by (x3) and (x5) leaves remainders 10 and 6, respectively. If the polynomial is divided by (x3)(x5), then the remainder is

A
2x+16
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B
16
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C
2x16
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D
60
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Solution

The correct option is B 2x+16
Given, P(x)=(x3)(x5)Q(x)+(ax+b)
Also given, P(3)=10 and P(5)=6
3a+b=10 ...(i)
And 5a+b=6 ...(ii)
Subtracting both the equations, we get
a=2
Putting this value in equation (i) we get
3(2)+b=10
b=10+6
b=16
Thus a=2 and b=16
Therefore, remainder 2x+16.

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