Let P(x) be a polynomial, which when divided by (x−3) and (x−5) leaves remainders 10 and 6, respectively. If the polynomial is divided by (x−3)(x−5), then the remainder is
A
−2x+16
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B
16
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C
2x−16
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D
60
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Solution
The correct option is B−2x+16 Given, P(x)=(x−3)(x−5)Q(x)+(ax+b) Also given, P(3)=10 and P(5)=6 ⇒3a+b=10 ...(i) And 5a+b=6 ...(ii) Subtracting both the equations, we get
a=−2
Putting this value in equation (i) we get
3(−2)+b=10
⇒b=10+6
⇒b=16 Thus a=−2 and b=16 Therefore, remainder −2x+16.