CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let P(x) be a polynomial, which when divided by (x3) and (x5) leaves remainders 10 and 6, respectively. If the polynomial is divided by (x3)(x5), then the remainder is

A
2x+16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
60
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2x+16
Given, P(x)=(x3)(x5)Q(x)+(ax+b)
Also given, P(3)=10 and P(5)=6
3a+b=10 ...(i)
And 5a+b=6 ...(ii)
Subtracting both the equations, we get
a=2
Putting this value in equation (i) we get
3(2)+b=10
b=10+6
b=16
Thus a=2 and b=16
Therefore, remainder 2x+16.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Some Functions and Their Graphs
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon