Let P(x) be a polynomial with degree 2017 and leading co-efficient unity such that P(0) = 2016, P(1) = 2015, P(2) = 2014,….P(2016) = 0 then the value of P(2017) = n! - awhere n and a are natural number then value of (n + a)
A
2018
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B
2017
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C
2019
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D
2016
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Solution
The correct option is A 2018 P(x)−2016+x=x(x−1)(x−2)(x−3)……(x−2016) Put x=2017 P(2017) + 1 = (2017)!