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Question

Let P(x) be a quadratic polynomial with real coefficients satisfying x22x+2P(x)2x24x+3 for all xR. Suppose P(7)=64, then the value of P(13) is

A
242
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B
252
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C
253
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D
201
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Solution

The correct option is C 253
Observe that x22x+2=(x1)2+1
and 2x24x+3=2(x1)2+1
Then (x1)2+1P(x)2(x1)2+1
Since P(x) is a quadratic polynomial, we get
P(x)=a(x1)2+1 for some a[1,2]

P(7)=64a=74
P(x)=74(x1)2+1
Hence, P(13)=253

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