Let P={x|x is a multiple of 3 and less than 100 ,x∈N} Q={x|x is a multiple of 10 and less than 100, x∈N}
A
Q⊂P
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B
P∪Q={x|x is multiple of 30;x∈N}
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C
P∩Q=ϕ
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D
P∩Q={x|x is a multiple of 30;x∈N}
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Solution
The correct option is DP∩Q={x|x is a multiple of 30;x∈N} P = {3,6,9,12,15,18,21,24,27,30...,60,...,90,....,99} Q = {10,20,30,40,50,60,70,80,90} Then looking at the multiple choices we get P∩Q= {30,60,90} ⇒P ∩ Q = {x∣ x is a multiple of 30 xϵ N}