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Question

Let PM be the perpendicular from the point P(1,2,3) to the xy plane. If OP makes an angle θ with the positive direction of the z-axis and OM makes an angle ϕ with the positive direction of x-axis, where O is the origin and θ and ϕ are acute angles, then

A
cosθcosϕ=114
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B
sinθsinϕ=214
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C
tanϕ =2
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D
tanθ=53
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Solution

The correct option is D tanθ=53
If P be (x,y,z), then from the figure,
x=rsinθcosϕ,y=rsinθsinϕ and z=rcosθ
1=rsinθcosϕ,2=rsinθsinϕ and 3=rcosθ
12+22+32=r2
r=±14
sinθcosϕ=114,
sinθsinϕ=214 and cosθ=314
(neglecting negative sign as θ and ϕ are acute)

sinθsinϕsinθcosϕ=21
tanϕ=2
Also, tanθ=53

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