Let PQ be a focal chord of the parabola y2=4ax. The tangents to the parabola at P and Q meet at a point lying on the line y=2x+a,a>0.
Length of chord PQ
A
7a
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B
5a
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C
2a
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D
3a
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Solution
The correct option is B 5a
Since, R[−a,a(t−1t)]lies on y=2x+a ⇒a⋅(t−1t)=−2a+a⇒t−1t=−1 Thus, length of focal chord =a(t+1t)2=a{(t−1t)2+4}=5a