1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Let pqr, qrp and rpq be three digit numbers. Then, pqr + qrp + rpq is divisible by:

A
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
37
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
47
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 37pqr = 100p + 10q + r qrp = 100q + 10r + p rpq = 100r + 10p + q Adding all three, pqr + qrp + rpq = 100p + 10q + r + 100q + 10r + p + 100r + 10p + q pqr + qrp + rpq = 100(p + q +r) + 10(p + q + r) + (p + q + r) pqr + qrp + rpq = (100 + 10 + 1)(p + q + r) = 111(p + q +r) pqr + qrp + rpq = 3 x 37(p + q + r) Hence, pqr + qrp + rpq is divisible by 37

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Addition and Subtraction of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program