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Question

Let PQRS be a kite such that PQ > PS. Prove that PQR > PSR. (Hint: Join QS).

 


Solution

In any triangle, the angle opposite to a longer side is greater.

Here, PS = SR and PQ = QR

It is given that PQ > PS

In triangles SPQ and QRS:

Adding both inequalities, we get:

 


Mathematics
Mathematics
Standard VIII

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