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Question

Let PS be the median of a triangle with vertices P(2,2), Q(6,1) and R(7,3). The equation of the line passing through (1,1) and parallel to PS is

A
2x9y7=0
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B
2x9y11=0
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C
2x+9y11=0
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D
2x+9y+7=0
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Solution

The correct option is D 2x+9y+7=0
Median through P bisects QR.
Hence, coordinates of S are (6+72,1+32)=(132,1)
Slope of PS is 1213/22=29
Equation of line passing through (1,1) and parallel to PS is y+1=29(x1)
2x+9y+7=0

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