Let PS be the median of a triangle with vertices P(2,2),Q(6,−1) and R(7,3). The equation of the line passing through (1,−1) and parallel to PS is
A
2x−9y−7=0
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B
2x−9y−11=0
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C
2x+9y−11=0
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D
2x+9y+7=0
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Solution
The correct option is D2x+9y+7=0 Median through P bisects QR. Hence, coordinates of S are (6+72,−1+32)=(132,1) Slope of PS is 1−213/2−2=−29 Equation of line passing through (1,−1) and parallel to PS is y+1=−29(x−1) ⇒2x+9y+7=0